Has anyone used one of the kits or manuals to convert their car to a water/fuel vehicle?

teacher93514 asked:


I have visited many sites that claim a simple hydrogen conversion unit will give you 45% – 65% increase in fuel efficiency, but none appear to have any feedback from actual users. I’d like to hear from someone who has actually used this technology on a regular gas burning car and knows how easy or difficult the conversion was to install and if the gas savings are realistic.
As for the chemistry being all wrong, I think not. I’ve seen the newsreel footage of the Japanese car that runs completely on water alone, using a hydrogen conversion engine. I know the water-fueled engine works. I just want to know if my old car can take advantage of this technology or if I have to wait and buy a new car when the Japanese car goes into production.

As for American car makers jumping on the new technology–Are you kidding me? Detroit is in bed with Big Oil, or haven’t you noticed? The VW bug came to American when I was still too young to drive, but Detroit didn’t bother to make anything to rival it until over 20 years later, and that was not due to their altruism but due to former gas-guzzler customers buying German and Japanese and Italian economy cars. I have no problem with not buying American if American car manufacturers have no problem gouging me for a pollution-mobile.

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How to Calculate the Energy Released for an Electron in the Hydrogen Atom?

hydrogen conversion
habitxo asked:


I’m extremely rusty in chemistry seeing as how I took Chem111 during my freshman year and am now a junior taking Chem112 and am having problems with this problem.

Calculate the energy released for an electron in the hydrogen atom that undergoes a transition from n = 2 to n = 4.

Multiple Choice Answers:
a. 4.09 X 10-19 J
b. 8.39 X 10-20 J
c. 7.46 X 10-32 J
d. 3.29 X 10-18 J
e. 5.39 X 10-21 J

Now, am I doing this right and using the correct formula?

I’m using the formula Ephoton = hv = hRH (1/n^2(low) – 1/n^2(high)) where hRH is 3.290×10^15 s^-1

so I get:
hv=3.290×10^15 s^-1 (1/4 – 1/16)
hv=3.290/0.1875
hv=17.54667
conversion to Joules:
17.54667 x 6.2415×10^18 = 1.095 x 10^20???

It’s all wrong so I threw it up there for someone to pick it apart and show me where I was wrong and if you could kindly show me the correct way, thanks!

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