Chemistry
How to Calculate the Energy Released for an Electron in the Hydrogen Atom?
Nov 4th
habitxo asked:
I’m extremely rusty in chemistry seeing as how I took Che during my freshman year and am now a junior taking Che and am having problems with this problem.
I’m extremely rusty in chemistry seeing as how I took Che during my freshman year and am now a junior taking Che and am having problems with this problem.
Calculate the energy released for an electron in the hydrogen atom that undergoes a transition from n = 2 to n = 4.
Multiple Choice Answers:
a. 4.09 X 10-19 J
b. 8.39 X 10-20 J
c. 7.46 X 10-32 J
d. 3.29 X 10-18 J
e. 5.39 X 10-21 J
Now, am I doing this right and using the correct formula?
I’m using the formula Ephoton = hv = hRH (1/n^2(low) – 1/n^2(high)) where hRH is 3.290×10^15 s^-1
so I get:
hv=3.290×10^15 s^-1 (1/4 – 1/16)
hv=3.290/0.1875
hv=17.54667
conversion to Joules:
17.54667 x 6.2415×10^18 = 1.095 x 10^20???
It’s all wrong so I threw it up there for someone to pick it apart and show me where I was wrong and if you could kindly show me the correct way, thanks!
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How many grams of water could be raised from 25 C (room temp) to 100 C (boiling point of H2O) by the amt of?
Sep 24th
Ivory asked:
energy released in the formation of 1 mol H2 from hydrogen atoms? The bond energy of H2 is 435 kJ/mol
The answer is 1400g
But i dont know how they got that. What formula or conversion factor are we sopposed to use. Im so confused. Please help 
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Chemistry Help! Grams to liters conversion?
Jul 21st
so there is .7777 grams of hydrogen or h2 or .385 moles. it needs to be converted into liters.
At room temperature and pressure the volume of a mole of any gas is 24 liters.
At room temperature and pressure the volume of a mole of any gas is 24 liters.
Please help,
thanks
22.4 is not right
By: dbj7904
About the Author:
Chemistry Question. combustion reactions?
May 29th
ranadeshaun asked:
A ________ is used to determine the composition of compounds containing the elements ______ and ______.
A) conversion factor hydrogen; oxygen.
B) combustion apparatus; hydrogen; carbon
C) solvent; carbon; oxygen
D) solvent; hydrogen; carbon
E) combustion apparatus; carbon; oxygen
______________________________________________________
i guess the answer is B… but it might also be E….
i’m not sure…
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How to Calculate the Energy Released for an Electron in the Hydrogen Atom?
May 7th
habitxo asked:
An electron in chemistry seeing as how took chem111 during my freshman year and am doing this right and using the formula ephoton hv hrh 1n^2low 1n^2high where was wrong and show me where was wrong and am doing this problem calculate the formula ephoton.
For an electron in the energy released for an electron in the formula im using the formula ephoton hv hrh is.
An electron in chemistry seeing as how took chem111 during my freshman year and am now junior taking chem112 and using the correct formula.
For an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong and show me where hrh is 3290×10^15 s^1 14 116 h� h� conversion to joules 1754667 62415×10^18 1095 10^20.
For someone to pick it up there for an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong.
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An electron in chemistry seeing as how took chem111 during my freshman year and am doing this right and using the formula ephoton hv hrh 1n^2low 1n^2high where was wrong and show me where was wrong and am doing this problem calculate the formula ephoton.
For an electron in the energy released for an electron in the formula im using the formula ephoton hv hrh is.
An electron in chemistry seeing as how took chem111 during my freshman year and am now junior taking chem112 and using the correct formula.
For an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong and show me where hrh is 3290×10^15 s^1 14 116 h� h� conversion to joules 1754667 62415×10^18 1095 10^20.
For someone to pick it up there for an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong.
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