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	<title>Hydrogen Car Kit &#187; Chemistry</title>
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	<link>http://www.hydrogen-car-kit.org</link>
	<description>Hydrogen Car Kits And Related Products</description>
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		<item>
		<title>The conversion factor that is used to change mass to moles is?</title>
		<link>http://www.hydrogen-car-kit.org/the-conversion-factor-that-is-used-to-change-mass-to-moles-is/</link>
		<comments>http://www.hydrogen-car-kit.org/the-conversion-factor-that-is-used-to-change-mass-to-moles-is/#comments</comments>
		<pubDate>Sat, 27 Jun 2009 02:46:55 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Conversion Factor]]></category>
		<category><![CDATA[Moles]]></category>

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		<description><![CDATA[No N asked: Create a video blog]]></description>
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<div><em><strong>No N</strong> asked: </em><br/><br/><br/><br/><br/><a href='http://mycaffeinatedcontent.com'>Create a video blog</a></div>
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		<title>How to Calculate the Energy Released for an Electron in the Hydrogen Atom?</title>
		<link>http://www.hydrogen-car-kit.org/how-to-calculate-the-energy-released-for-an-electron-in-the-hydrogen-atom-2/</link>
		<comments>http://www.hydrogen-car-kit.org/how-to-calculate-the-energy-released-for-an-electron-in-the-hydrogen-atom-2/#comments</comments>
		<pubDate>Tue, 04 Nov 2008 16:05:57 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Conversion]]></category>
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		<description><![CDATA[habitxo asked: I&#8217;m extremely rusty in chemistry seeing as how I took Chem111 during my freshman year and am now a junior taking Chem112 and am having problems with this problem. Calculate the energy released for an electron in the &#8230; <a href="http://www.hydrogen-car-kit.org/how-to-calculate-the-energy-released-for-an-electron-in-the-hydrogen-atom-2/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<div><em><strong>habitxo</strong> asked: </em><br/><br/><br/>I&#8217;m extremely rusty in chemistry seeing as how I took Chem111 during my freshman year and am now a junior taking Chem112 and am having problems with this problem.</p>
<p>Calculate the energy released for an electron in the hydrogen atom that undergoes a transition from n = 2 to n = 4.</p>
<p>Multiple Choice Answers:<br />
a. 4.09 X 10-19 J<br />
b. 8.39 X 10-20 J<br />
c. 7.46 X 10-32 J<br />
d. 3.29 X 10-18 J<br />
e. 5.39 X 10-21 J</p>
<p>Now, am I doing this right and using the correct formula?</p>
<p>I&#8217;m using the formula Ephoton = hv = hRH (1/n^2(low) &#8211; 1/n^2(high)) where hRH is 3.290&#215;10^15 s^-1</p>
<p>so I get:<br />
hv=3.290&#215;10^15 s^-1 (1/4 &#8211; 1/16)<br />
hv=3.290/0.1875<br />
hv=17.54667<br />
conversion to Joules:<br />
17.54667 x 6.2415&#215;10^18 = 1.095 x 10^20???</p>
<p>It&#8217;s all wrong so I threw it up there for someone to pick it apart and show me where I was wrong and if you could kindly show me the correct way, thanks!<br/><br/><a href='http://kansieo.com/members'>Caffeinated Content for WordPress</a></div>
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		<title>How many grams of water could be raised from 25 C (room temp) to 100 C (boiling point of H2O) by the amt of?</title>
		<link>http://www.hydrogen-car-kit.org/how-many-grams-of-water-could-be-raised-from-25-c-room-temp-to-100-c-boiling-point-of-h2o-by-the-amt-of-2/</link>
		<comments>http://www.hydrogen-car-kit.org/how-many-grams-of-water-could-be-raised-from-25-c-room-temp-to-100-c-boiling-point-of-h2o-by-the-amt-of-2/#comments</comments>
		<pubDate>Thu, 25 Sep 2008 00:13:30 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Amt]]></category>
		<category><![CDATA[Boiling Point]]></category>
		<category><![CDATA[Bond Energy]]></category>
		<category><![CDATA[Conversion Factor]]></category>
		<category><![CDATA[H2]]></category>
		<category><![CDATA[H2o]]></category>
		<category><![CDATA[Hydrogen Atoms]]></category>
		<category><![CDATA[Ivory]]></category>
		<category><![CDATA[Kj Mol]]></category>
		<category><![CDATA[Room Temp]]></category>

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		<description><![CDATA[Ivory asked: energy released in the formation of 1 mol H2 from hydrogen atoms? The bond energy of H2 is 435 kJ/mol The answer is 1400g But i dont know how they got that. What formula or conversion factor are &#8230; <a href="http://www.hydrogen-car-kit.org/how-many-grams-of-water-could-be-raised-from-25-c-room-temp-to-100-c-boiling-point-of-h2o-by-the-amt-of-2/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
			<content:encoded><![CDATA[<p>Ivory asked: <br/><br/><br/>energy released in the formation of 1 mol H2 from hydrogen atoms? The bond energy of H2 is 435 kJ/mol</p>
<p>The answer is 1400g</p>
<p>But i dont know how they got that. What formula or conversion factor are we sopposed to use. Im so confused. Please help <img src='http://www.hydrogen-car-kit.org/wp-includes/images/smilies/icon_sad.gif' alt=':(' class='wp-smiley' /> <br/><br/><a href='http://mycaffeinatedcontent.com'>Website content</a></p>
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		<title>Brown Spots in Hydrogen Fuel Cell?</title>
		<link>http://www.hydrogen-car-kit.org/brown-spots-in-hydrogen-fuel-cell/</link>
		<comments>http://www.hydrogen-car-kit.org/brown-spots-in-hydrogen-fuel-cell/#comments</comments>
		<pubDate>Sat, 20 Sep 2008 01:02:49 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Car Kit]]></category>
		<category><![CDATA[Hydrogen Car]]></category>
		<category><![CDATA[Hydrogen Cell]]></category>
		<category><![CDATA[Hydrogen Fuel Cell]]></category>
		<category><![CDATA[Oxygen]]></category>
		<category><![CDATA[Toy Car]]></category>

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		<description><![CDATA[Ma77hew asked: Caffeinated Content &#8211; Members-Only Content for WordPress]]></description>
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<div><em><strong>Ma77hew</strong> asked: </em><br/><br/><br/><br/><br/><a href='http://kansieo.com/members'>Caffeinated Content &#8211; Members-Only Content for WordPress</a></div>
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		<item>
		<title>Conversion of H2O2 to O2?</title>
		<link>http://www.hydrogen-car-kit.org/conversion-of-h2o2-to-o2-2/</link>
		<comments>http://www.hydrogen-car-kit.org/conversion-of-h2o2-to-o2-2/#comments</comments>
		<pubDate>Mon, 21 Jul 2008 23:12:32 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Conversion]]></category>
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		<description><![CDATA[Mark T asked: Website content]]></description>
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<div><em><strong>Mark T</strong> asked: </em><br/><br/><br/><br/><br/><a href='http://mycaffeinatedcontent.com'>Website content</a></div>
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		<title>Chemistry Help! Grams to liters conversion?</title>
		<link>http://www.hydrogen-car-kit.org/chemistry-help-grams-to-liters-conversion-2/</link>
		<comments>http://www.hydrogen-car-kit.org/chemistry-help-grams-to-liters-conversion-2/#comments</comments>
		<pubDate>Mon, 21 Jul 2008 11:22:36 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Chemistry Help]]></category>
		<category><![CDATA[Grams To Liters]]></category>
		<category><![CDATA[Grams To Liters Conversion]]></category>
		<category><![CDATA[H2]]></category>
		<category><![CDATA[Hydrogen]]></category>
		<category><![CDATA[Mole]]></category>
		<category><![CDATA[Moles]]></category>
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		<description><![CDATA[so there is .7777 grams of hydrogen or h2 or .385 moles. it needs to be converted into liters. At room temperature and pressure the volume of a mole of any gas is 24 liters. Please help, thanks 22.4 is &#8230; <a href="http://www.hydrogen-car-kit.org/chemistry-help-grams-to-liters-conversion-2/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
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<div>so there is .7777 grams of hydrogen or h2 or .385 moles.  it needs to be converted into liters.<br />
At room temperature and pressure the volume of a mole of any gas is 24 liters.</p>
<p>Please help,</p>
<p>thanks<br />
22.4 is not right<br/><br/><em>By: <strong>dbj7904</strong></em><br/><br/><strong>About the Author:</strong>
<div style="border: thin solid gray; background-color: #E2E089; padding:1em;"></div>
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		<title>i hane read that by using j.j thomsan effect if gases are allowed to expand from compressed state then they liquify.LINDS device prectical and demonstrated this effect BUT WHY hydrogen and helium cant be liquify?and do  air conditioner also use same phenomenan?</title>
		<link>http://www.hydrogen-car-kit.org/i-hane-read-that-by-using-jj-thomsan-effect-if-gases-are-allowed-to-expand-from-compressed-state-then-they-liquifylinds-device-prectical-and-demonstrated-this-effect-but-why-hydrogen-and-helium-cant/</link>
		<comments>http://www.hydrogen-car-kit.org/i-hane-read-that-by-using-jj-thomsan-effect-if-gases-are-allowed-to-expand-from-compressed-state-then-they-liquifylinds-device-prectical-and-demonstrated-this-effect-but-why-hydrogen-and-helium-cant/#comments</comments>
		<pubDate>Thu, 10 Jul 2008 23:12:20 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
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		<description><![CDATA[joy happy asked: Website content]]></description>
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<div><em><strong>joy happy</strong> asked: </em><br/><br/><br/><br/><br/><a href='http://mycaffeinatedcontent.com'>Website content</a></div>
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		<title>Chemistry Question. combustion reactions?</title>
		<link>http://www.hydrogen-car-kit.org/chemistry-question-combustion-reactions/</link>
		<comments>http://www.hydrogen-car-kit.org/chemistry-question-combustion-reactions/#comments</comments>
		<pubDate>Thu, 29 May 2008 21:43:57 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Chemistry Question]]></category>
		<category><![CDATA[Combustion Reactions]]></category>
		<category><![CDATA[Composition]]></category>
		<category><![CDATA[Compounds]]></category>
		<category><![CDATA[Conversion Factor]]></category>
		<category><![CDATA[Elements]]></category>
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		<description><![CDATA[ranadeshaun asked: A ________ is used to determine the composition of compounds containing the elements ______ and ______. A) conversion factor; hydrogen; oxygen. B) combustion apparatus; hydrogen; carbon C) solvent; carbon; oxygen D) solvent; hydrogen; carbon E) combustion apparatus; carbon; &#8230; <a href="http://www.hydrogen-car-kit.org/chemistry-question-combustion-reactions/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
			<content:encoded><![CDATA[<p>ranadeshaun asked: <br/><br/><br/>A ________ is used to determine the composition of compounds containing the elements ______ and ______.</p>
<p>A) conversion factor;   hydrogen;    oxygen.<br />
B) combustion apparatus;   hydrogen;   carbon<br />
C) solvent;   carbon;  oxygen<br />
D) solvent;   hydrogen;   carbon<br />
E) combustion apparatus;  carbon;  oxygen </p>
<p>______________________________________________________</p>
<p>i guess the answer is B&#8230; but it might also be E&#8230;.<br />
i&#8217;m not sure&#8230;<br/><br/><a href='http://kansieo.com/'>Caffeinated Content</a></p>
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		<title>Special Effects?</title>
		<link>http://www.hydrogen-car-kit.org/special-effects/</link>
		<comments>http://www.hydrogen-car-kit.org/special-effects/#comments</comments>
		<pubDate>Thu, 08 May 2008 21:46:21 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
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		<category><![CDATA[Flouride]]></category>
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		<category><![CDATA[Helium 3]]></category>
		<category><![CDATA[Hydrogen Iodide]]></category>
		<category><![CDATA[Iodine]]></category>
		<category><![CDATA[Magnesium Chloride]]></category>
		<category><![CDATA[Molar Masses]]></category>
		<category><![CDATA[Mole Ratios]]></category>
		<category><![CDATA[Moles]]></category>
		<category><![CDATA[Number Of Atoms]]></category>
		<category><![CDATA[Special Effects]]></category>
		<category><![CDATA[Stoichiometry Problem]]></category>
		<category><![CDATA[Synthesis Reactions]]></category>
		<category><![CDATA[Zinc]]></category>

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		<description><![CDATA[chemhelp1990 asked: Caffeinated Content for WordPress]]></description>
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<div><em><strong>chemhelp1990</strong> asked: </em><br/><br/><br/><br/><br/><a href='http://kansieo.com'>Caffeinated Content for WordPress</a></div>
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		<title>How to Calculate the Energy Released for an Electron in the Hydrogen Atom?</title>
		<link>http://www.hydrogen-car-kit.org/how-to-calculate-the-energy-released-for-an-electron-in-the-hydrogen-atom/</link>
		<comments>http://www.hydrogen-car-kit.org/how-to-calculate-the-energy-released-for-an-electron-in-the-hydrogen-atom/#comments</comments>
		<pubDate>Wed, 07 May 2008 21:19:41 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Chemistry]]></category>
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		<description><![CDATA[habitxo asked: An electron in chemistry seeing as how took chem111 during my freshman year and am doing this right and using the formula ephoton hv hrh 1n^2low 1n^2high where was wrong and show me where was wrong and am &#8230; <a href="http://www.hydrogen-car-kit.org/how-to-calculate-the-energy-released-for-an-electron-in-the-hydrogen-atom/">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
			<content:encoded><![CDATA[<div style="float:left; padding: 12px"><a href="/wp-content/uploads/cc/hydrogen_conversion46.jpg"><img src="/wp-content/uploads/cc/hydrogen_conversion46.jpg" title='hydrogen conversion' alt='hydrogen conversion' /></a></div>
<div><em><strong>habitxo</strong> asked: </em><br/><br/><br/><br/>An electron in chemistry seeing as how took chem111 during my freshman year and am doing this right and using the formula ephoton hv hrh 1n^2low 1n^2high where was wrong and show me where was wrong and am doing this problem calculate the formula ephoton.<br />
<br/>For an electron in the energy released for an electron in the formula im using the formula ephoton hv hrh is.<br />
<br/>An electron in chemistry seeing as how took chem111 during my freshman year and am now junior taking chem112 and using the correct formula.<br />
<br/>For an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong and show me where hrh is 3290&#215;10^15 s^1 14 116 hv329001875 hv1754667 conversion to joules 1754667 62415&#215;10^18 1095 10^20.<br />
<br/>For someone to pick it up there for an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong.<br />
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