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	<title>Comments on: How many grams of water could be raised from 25 C (room temp) to 100 C (boiling point of H2O) by the amt of?</title>
	<atom:link href="http://www.hydrogen-car-kit.org/how-many-grams-of-water-could-be-raised-from-25-c-room-temp-to-100-c-boiling-point-of-h2o-by-the-amt-of-2/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.hydrogen-car-kit.org/how-many-grams-of-water-could-be-raised-from-25-c-room-temp-to-100-c-boiling-point-of-h2o-by-the-amt-of-2/</link>
	<description>Hydrogen Car Kits And Related Products</description>
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		<title>By: Idyllic</title>
		<link>http://www.hydrogen-car-kit.org/how-many-grams-of-water-could-be-raised-from-25-c-room-temp-to-100-c-boiling-point-of-h2o-by-the-amt-of-2/comment-page-1/#comment-241</link>
		<dc:creator>Idyllic</dc:creator>
		<pubDate>Thu, 25 Sep 2008 02:57:34 +0000</pubDate>
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		<description>Enthalpie = (CP x T x m) / (1000 x n)  Wanneer enthalpie is 435, CP is 4,18 (energie-dichtheid van water), T is de verandering in temperatuur (100 - 25), m is de massa van water (haar wat je wilt), n is de mol van waterstof gas (1) .  Daarom opnieuw geordend geeft:  m = (enthalpie x 1000 x n) / (CP x T)  Het antwoord is 1387g = 1400g (2 s.f.)</description>
		<content:encoded><![CDATA[<p>Enthalpie = (CP x T x m) / (1000 x n)  Wanneer enthalpie is 435, CP is 4,18 (energie-dichtheid van water), T is de verandering in temperatuur (100 &#8211; 25), m is de massa van water (haar wat je wilt), n is de mol van waterstof gas (1) .  Daarom opnieuw geordend geeft:  m = (enthalpie x 1000 x n) / (CP x T)  Het antwoord is 1387g = 1400g (2 s.f.)</p>
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