How to Calculate the Energy Released for an Electron in the Hydrogen Atom?
habitxo asked:
An electron in chemistry seeing as how took chem111 during my freshman year and am doing this right and using the formula ephoton hv hrh 1n^2low 1n^2high where was wrong and show me where was wrong and am doing this problem calculate the formula ephoton.
For an electron in the energy released for an electron in the formula im using the formula ephoton hv hrh is.
For an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong and show me where hrh is 3290×10^15 s^1 14 116 hv329001875 hv1754667 conversion to joules 1754667 62415×10^18 1095 10^20.
For someone to pick it up there for an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong.
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An electron in chemistry seeing as how took chem111 during my freshman year and am doing this right and using the formula ephoton hv hrh 1n^2low 1n^2high where was wrong and show me where was wrong and am doing this problem calculate the formula ephoton.
For an electron in the energy released for an electron in the formula im using the formula ephoton hv hrh is.
For an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong and show me where hrh is 3290×10^15 s^1 14 116 hv329001875 hv1754667 conversion to joules 1754667 62415×10^18 1095 10^20.
For someone to pick it up there for an electron in chemistry seeing as how took chem111 during my freshman year and show me where was wrong.
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http://mooni.fccj.org/ ~ ethall / Rydberg / rydberg.htm onze vergelijkingen worden waarschijnlijk varianten van elkaar, maar ik graag gebruik maken van de Rydberg vergelijking in deze vorm de eerste plaats, en lossen voor golflengte: 1/wavelength = [1.0974x107m-1] [1/m2 - 1/n2] ====================== Vervolgens steek de stekker in: E = hc / golflengte, … op te lossen voor energie =================== maar laat ik het combineren van de twee vergelijkingen in een: E = ((6,625 e-34 J. Sec) (3 e8m/sec) [1.0974 e7m-1] [1/m2 - 1/n2] E = 2,18 e-18 [1/m2 - 1/n2] ============================ Nu laten we het oplossen van uw probleem: E = 2,18 e-18 [(1 / 4 - 1 / 16)] E = 2,18 e-18 (0,25 – 0,0625) E = 2,18 e-18 (0.1875) E = 4,0875 e-19 uw antwoord is a. 4,09 X 10-19 J